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1 Atomic Structure and Properties 2 Compound Structure and Properties 3 Properties of Substances and Mixtures 4 Chemical Reactions 5 Kinetics 6 Thermochemistry 7 Equilibrium 8 Acids and Bases 9 Thermodynamics and Electrochemistry

8 Acids and Bases

8.1 Introduction to Acids and Bases 8.2 pH and pOH of Strong Acids and Bases 8.3 Weak Acid and Base Equilibria 8.4 Acid-Base Reactions and Buffers 8.5 Acid-Base Titrations 8.6 Molecular Structure of Acids and Bases 8.7 pH and pK a 8.8 Properties of Buffers 8.9 Henderson- Hasselbalch Equation 8.10 Buffer Capacity 8.11 pH and Solubility

The Henderson-Hasselbalch Equation

Learning Objective 8.9.A Identify the pH of a buffer solution based on the identity and concentrations of the conjugate acid-base pair used to create the buffer.

Quick Notes

  • The Henderson–Hasselbalch equation is used to calculate the pH of a buffer solution.
    • It links pH, pKa, and the concentration ratio of conjugate base to acid.
  • Small additions of acid or base do not significantly change the pH of a well-prepared buffer.

Full Notes

What is the Henderson–Hasselbalch Equation?

The Henderson–Hasselbalch equation links the pH of a buffer solution to the concentration of the weak acid (HA) and its conjugate base (A).

AP Chemistry graphic of the Henderson–Hasselbalch equation showing pH = pKa + log([A−]/[HA]).

Where:

How It Works

Buffering Action

When small amounts of acid or base are added to a buffered solution the ratio [A]/[HA] changes only slightly and therefore, the pH changes very little. This is why buffers are effective at resisting pH changes.

Worked Example

Q: What is the pH of a buffer solution that is 0.20 M acetic acid (CH3COOH) and 0.10 M sodium acetate (CH3COONa)? The pKa of acetic acid is 4.76.

  1. Identify HA = CH3COOH, A = CH3COO; [HA] = 0.20 M, [A] = 0.10 M, pKa = 4.76.
  2. Apply Henderson–Hasselbalch
    pH = pKa + log\([A]/[HA]\) = 4.76 + log(0.10 / 0.20).
  3. Evaluate ratio
    0.10 / 0.20 = 0.50 → log(0.50) ≈ −0.30.
  4. Calculate pH
    pH = 4.76 + (−0.30) = 4.46.

Answer: The buffer’s pH is 4.46. Because [A] < [HA], pH is below pKa, consistent with the rule above.

Summary